document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333323>Question 333323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A store mixes coffee A worth $10. per kilogram and coffee B worth $12. per kilogram. The mixture is to sell for $11. per kilogram. Find how much should be used to make a 480 kilogram mixture.\r<BR>\n" );
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document.write( "How many kilograms of coffee A should be in the mix?\r<BR>\n" );
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document.write( "How many kilograms of coffee B should be in the mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238834 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> coffee A worth $10. per kilogram <BR>\n" );
document.write( "coffee B worth $12. per kilogram. <BR>\n" );
document.write( "mixture is to sell for $11. per kilogram. <BR>\n" );
document.write( "480 kilogram mixture.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "coffee A quantity be x kg  $10<BR>\n" );
document.write( "coffee B quantity will be 480-x kg. $12<BR>\n" );
document.write( "Mixture $11 480 kg<BR>\n" );
document.write( "..<BR>\n" );
document.write( "10x+12(480-x)= 11*480<BR>\n" );
document.write( "10x+5760-12x=5280<BR>\n" );
document.write( "-2x=5280-5760<BR>\n" );
document.write( "-2x=-480<BR>\n" );
document.write( "x= 240 kg Coffee A<BR>\n" );
document.write( "Coffee B = 240 kgs.<BR>\n" );
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