document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333321>Question 333321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a silly question, but I'm in doubt for trying to resolve (6v+3)(6v+3). I found it 6v^2+36v+9. Can I simplify this dividing by 3,  to 2v^2+12v+3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238832 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238832\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6v+3)(6v+3)<BR>\n" );
document.write( "= 36v^2+36v+9    ( it is not 6v^2)<BR>\n" );
document.write( "=9(4v^2+4v+1)<BR>\n" );
document.write( "=9(2v+1)^2 </SPAN>\n" );
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