document.write( "Question 333310: 1. Suppose a survey of 890 families with 5 children was done
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Algebra.Com's Answer #238828 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "It depends. What are your assumptions regarding the probability of conception of a boy vs. a girl? If you presume 50/50, which is totally false, then you would proceed thus:\r
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\n" ); document.write( "\n" ); document.write( "The probability of successes in trials where is the probability of success on any given trial is given by:\r
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\n" ); document.write( "\n" ); document.write( "Where is the number of combinations of things taken at a time and is calculated by \r
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\n" ); document.write( "\n" ); document.write( "To calculate the probability of all boys in 5, you would use:\r
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\n" ); document.write( "\n" ); document.write( "Fortunately, this reduces to a very simple calculation because \ 0\ \in\ \mathbb{Z}\">. And .\r
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\n" ); document.write( "\n" ); document.write( "Since the probability is 1/2, the probability of 5 girls is the same, so the probability of either is just two times either.\r
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\n" ); document.write( "\n" ); document.write( "If you want to assume the empirical probability of a boy being 105/205 or approximately 0.512, then you need to do:\r
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\n" ); document.write( "\n" ); document.write( "Once you decide on which probability to use, multiply by 890 to find the expected number.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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