document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333301>Question 333301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose a video store charges non-members $3 to rent a video. a membership cost $21 and then each video costs only $1.50 to rent. how many videos would you need to rent in order to justidy a membership? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238827 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> non-members $3 to rent a video. a membership cost $21 and then each video costs only $1.50 to rent.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Let number of videos to be rented be x<BR>\n" );
document.write( "21+1.5x < 3x<BR>\n" );
document.write( "add -1.5x<BR>\n" );
document.write( "21+1.5x-1.5x<3x-1.5x<BR>\n" );
document.write( "21< 3x-1.5x<BR>\n" );
document.write( "divide by 1.5<BR>\n" );
document.write( "21/1.5<x<BR>\n" );
document.write( "x> 14<BR>\n" );
document.write( "For x >  14 membeship would be a better deal </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );