document.write( "Question 333064: Please help me write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8.\r
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Algebra.Com's Answer #238798 by ankor@dixie-net.com(22740)\"\" \"About 
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write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8.
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\n" ); document.write( "Find the slope by putting the equation into the slope/intercept form (y=mx+b)
\n" ); document.write( "3x - 2y = 8
\n" ); document.write( "-2y = -3x + 8
\n" ); document.write( "y has to be positive, multiply by -1
\n" ); document.write( "2y = 3x - 8
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "y = \"3%2F2%29%29%29x+-+%7B%7B%7B8%2F2\"
\n" ); document.write( "y = \"3%2F2\"x - 4
\n" ); document.write( "Slope: m1 = \"3%2F2\"
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\n" ); document.write( "slope relationship of the slopes of perpendicular lines is m1*m2 = -1
\n" ); document.write( "find m2
\n" ); document.write( "\"3%2F2\"*m2 = -1
\n" ); document.write( "m2 = -1 * \"2%2F3\"
\n" ); document.write( "m2 = \"-2%2F3\" is the slope of the perpendicular line
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\n" ); document.write( "Find the equation using the point/slope form: y - y1 = m(x - x1)
\n" ); document.write( "m = \"-2%2F3\", x1 = -4, y1 = 6
\n" ); document.write( "y - 6 = \"-2%2F3\"(x - (-4))
\n" ); document.write( "y - 6 = \"-2%2F3\"(x + 4)
\n" ); document.write( "y - 6 = \"-2%2F3\"x + (-2/3)*4
\n" ); document.write( "y - 6 = \"-2%2F3\"x - \"8%2F3\"
\n" ); document.write( "y = \"-2%2F3\"x - \"8%2F3\" + 6
\n" ); document.write( "y = \"-2%2F3\"x - \"8%2F3\" + \"18%2F3\"
\n" ); document.write( "y = \"-2%2F3\"x + \"10%2F3\" is the equation of the perpendicular line
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\n" ); document.write( "Check by finding y when x = -4
\n" ); document.write( "y = \"-2%2F3\"(-4) + \"10%2F3\"
\n" ); document.write( "y = \"8%2F3\" + \"10%2F3\"
\n" ); document.write( "y = \"18%2F3\"
\n" ); document.write( "y = 6\r
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