document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333185>Question 333185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive odd integers is 35 more than twice the largest. Find them. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238704 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x represent the first odd integer. it follows then that the second ODD integer would be x+2 (note: x+1 represents the integer consecutive to x, however if x is odd, x+1 would be even, which does not fit our condition). finally, the last (largest) integer can be represented by (x+2)+2 = x+4\r<BR>\n" );
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document.write( "the question states: \r<BR>\n" );
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document.write( "the sum of 3 con...integers = 35 more(+) twice the largest (x+4)\r<BR>\n" );
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document.write( "..in math terms...\r<BR>\n" );
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document.write( "x+(x+2)+(x+4)=35+(2*(x+4))<BR>\n" );
document.write( "now we solve this equation<BR>\n" );
document.write( "3x+6=35+2x+8<BR>\n" );
document.write( "3x-2x=35+8-6<BR>\n" );
document.write( "x=37\r<BR>\n" );
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document.write( "let's check: 37, 39, and 41<BR>\n" );
document.write( "firstly 37+39+41=117<BR>\n" );
document.write( "secondly, 35 more than twice the largest value yields 35+ (41*2)=117\r<BR>\n" );
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document.write( "our solution works! </SPAN>\n" );
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