document.write( "Question 333178: Find the solution to each system by the substitution method.
\n" ); document.write( "10x+3y=8
\n" ); document.write( "2x+y=2 \n" ); document.write( "

Algebra.Com's Answer #238703 by benazir.sj@gmail.com(109) $\"\"$ $\"About$

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10x+3y=8-------------(1)
\n" ); document.write( "2x+y=2---------------(2)\r
\n" ); document.write( "\n" ); document.write( "multiply (2) by 3 ie,
\n" ); document.write( "3*2x+3*y=3*2
\n" ); document.write( "=> 6x+3y=6--------------(3)\r
\n" ); document.write( "\n" ); document.write( "now the equations are
\n" ); document.write( "10x+3y =8-----------(1)
\n" ); document.write( "6x+3y=6-------------(3)\r
\n" ); document.write( "\n" ); document.write( "subtract(1)-(3)
\n" ); document.write( "=> 4x=2
\n" ); document.write( "x=2/4
\n" ); document.write( "x =1/2
\n" ); document.write( "substitute the value x=1/2 in (1)
\n" ); document.write( "10x+3y =8
\n" ); document.write( "10*1/2+3y=8
\n" ); document.write( "5+3y=8
\n" ); document.write( "3y=8-5=3
\n" ); document.write( "3y=3
\n" ); document.write( "y=1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "proof:
\n" ); document.write( "put x=1/2 and y=1 in the given equation
\n" ); document.write( "10x+3y=8
\n" ); document.write( "10*1/2+3*1=8
\n" ); document.write( "5+3=8
\n" ); document.write( "8=8
\n" ); document.write( "RHS=LHS \n" ); document.write( "

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