document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38387>Question 38387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use this formula logb a= loga/ logb, find log2 1000.  I don't understand how you do this equation.  I tried many different things and nothing works.  Thanks, Christine </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23870 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is what is called \"the change of base\" formula...logb a= loga/ logb...the logs on the right side are to the base 10 (but could really be any base we choose)<BR>\n" );
document.write( "In this case, <BR>\n" );
document.write( "log2 1000, our b = 2 and our a = 1000, so that<BR>\n" );
document.write( "log2 1000 = log 1000 / log 2<BR>\n" );
document.write( "log2 1000 = 3 / .30103 = 9.97 or almost 10<BR>\n" );
document.write( "and that makes sense since<BR>\n" );
document.write( "2^10 = 1024 and just about 1000 </SPAN>\n" );
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