document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332999>Question 332999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length and the width of a rectangle are in the ratio 3:2. if the length is increased by 15 and the width is decreased by 5, the ratio of the length to the width becomes 3:1. find the length and the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238623 by </B><A HREF=/tutors/aboutme.mpl?userid=AAfter.Com><B>AAfter.Com(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AAfter.Com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length and width of the rectangle be l and w units<BR>\n" );
document.write( "Given,<BR>\n" );
document.write( "l/w = 3/2 => l = 3w/2<BR>\n" );
document.write( "and (l + 15)/(w - 5) = 3/1 => l + 15 = 3w - 15<BR>\n" );
document.write( "=> 3w = l + 30 = 3w/2 + 30<BR>\n" );
document.write( "=> 3w/2 = 30<BR>\n" );
document.write( "=> w = 20<BR>\n" );
document.write( "=> l = (3x20)/2 = 30<BR>\n" );
document.write( "Hence, the length and breadth of the rectangle are 30 and 20 units </SPAN>\n" );
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