document.write( "Question 332971: 4. Fundraising. The St. Mark’s Community Barbecue
\n" ); document.write( "served 250 dinners. A child’s plate cost $3.50 and
\n" ); document.write( "an adult’s plate cost $7.00. A total of $1347.50 was
\n" ); document.write( "collected. How many of each type of plate
\n" ); document.write( "was served?
\n" ); document.write( "

Algebra.Com's Answer #238604 by benazir.sj@gmail.com(109)\"\" \"About 
You can put this solution on YOUR website!
you have to solve this question by linear eqaution:\r
\n" ); document.write( "\n" ); document.write( "Let the childs plate =C
\n" ); document.write( "and the adult plate =A
\n" ); document.write( "total number of dinners =250
\n" ); document.write( "C+A=250----------------(1)\r
\n" ); document.write( "\n" ); document.write( "cost of chids plate =$3.50
\n" ); document.write( "cost of adults plate =$7.00
\n" ); document.write( "total cost =$1347.50
\n" ); document.write( "$3.50C + $7.00 A=$1347.50 ---------------(2)
\n" ); document.write( "now equate the equations (1) and (2)
\n" ); document.write( "C+A=$250
\n" ); document.write( "*7C+7A=7*250
\n" ); document.write( "7C+7A=1750------(x)
\n" ); document.write( "3.50C+7A=1347.50-----(2)
\n" ); document.write( "______________________________
\n" ); document.write( "(x)-(2) => 3.50C =402.5
\n" ); document.write( "C=402.5/3.5
\n" ); document.write( "C=115
\n" ); document.write( "C+A=250
\n" ); document.write( "A=250-115=135\r
\n" ); document.write( "\n" ); document.write( "Childs plate =115and adults plate =135\r
\n" ); document.write( "\n" ); document.write( "proof:
\n" ); document.write( "$3.50C + $7.00 A=$1347.50
\n" ); document.write( "$3.50*115 +$7*135 =$1347.50
\n" ); document.write( "$402.5+$945 =$1347.5
\n" ); document.write( "$1347.50=$1347.50
\n" ); document.write( "
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