document.write( "Question 332971: 4. Fundraising. The St. Mark’s Community Barbecue
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document.write( "served 250 dinners. A child’s plate cost $3.50 and
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document.write( "an adult’s plate cost $7.00. A total of $1347.50 was
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document.write( "collected. How many of each type of plate
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document.write( "was served? \n" );
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Algebra.Com's Answer #238604 by benazir.sj@gmail.com(109)![]() ![]() You can put this solution on YOUR website! you have to solve this question by linear eqaution:\r \n" ); document.write( "\n" ); document.write( "Let the childs plate =C \n" ); document.write( "and the adult plate =A \n" ); document.write( "total number of dinners =250 \n" ); document.write( "C+A=250----------------(1)\r \n" ); document.write( "\n" ); document.write( "cost of chids plate =$3.50 \n" ); document.write( "cost of adults plate =$7.00 \n" ); document.write( "total cost =$1347.50 \n" ); document.write( "$3.50C + $7.00 A=$1347.50 ---------------(2) \n" ); document.write( "now equate the equations (1) and (2) \n" ); document.write( "C+A=$250 \n" ); document.write( "*7C+7A=7*250 \n" ); document.write( "7C+7A=1750------(x) \n" ); document.write( "3.50C+7A=1347.50-----(2) \n" ); document.write( "______________________________ \n" ); document.write( "(x)-(2) => 3.50C =402.5 \n" ); document.write( "C=402.5/3.5 \n" ); document.write( "C=115 \n" ); document.write( "C+A=250 \n" ); document.write( "A=250-115=135\r \n" ); document.write( "\n" ); document.write( "Childs plate =115and adults plate =135\r \n" ); document.write( "\n" ); document.write( "proof: \n" ); document.write( "$3.50C + $7.00 A=$1347.50 \n" ); document.write( "$3.50*115 +$7*135 =$1347.50 \n" ); document.write( "$402.5+$945 =$1347.5 \n" ); document.write( "$1347.50=$1347.50 \n" ); document.write( " |