document.write( "Question 4867: To expand the logarithmic expression as much as possible:\r
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\n" ); document.write( "log10 (x-30)= 3- log10 x
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Algebra.Com's Answer #2386 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
i take it you mean \"ln+%28x%5E3%2F%28x-3%29%5E2%29\"? If so, it becomes\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28x%5E3%29+-+ln%28x-3%29%5E2\"
\n" ); document.write( "\"3ln%28x%29+-+2ln%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "solve \"log10+%28x-30%29=+3-+log10+x\"..I shall leave out the base, for ease of reading --> \"log%28x-30%29=+3+-+log%28x%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"log%28x-30%29+%2B+log%28x%29+=+3\"
\n" ); document.write( "\"log%28x%28x-30%29%29+=+3\"
\n" ); document.write( "\"log%28x%5E2-30x%29+=+3\"
\n" ); document.write( "\"x%5E2-30x+=+10%5E3\"
\n" ); document.write( "\"x%5E2-30x+=+1000\"
\n" ); document.write( "\"x%5E2-30x-1000+=+0\"\r
\n" ); document.write( "\n" ); document.write( "(x+20)(x-50) = 0\r
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\n" ); document.write( "\n" ); document.write( "so x+20 = 0 OR x-50=0\r
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\n" ); document.write( "\n" ); document.write( "so, x=-20 or x=50\r
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\n" ); document.write( "\n" ); document.write( "in terms of logs, you cannot have negatives, so x=-20 will not be allowed, so x=50 is your one and only answer.\r
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\n" ); document.write( "\n" ); document.write( "jon
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