document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332855>Question 332855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line that is perpendicular to the line 3x - 2y = 6 and passes through the point (-1,2). <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238573 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x - 2y = 6 and passes through the point (-1,2). <BR>\n" );
document.write( "-2y=-3x+6<BR>\n" );
document.write( "y=-3x/-2+6/-2<BR>\n" );
document.write( "y=3x/2-3 (red line)<BR>\n" );
document.write( "This line has a slope=3/2<BR>\n" );
document.write( "Thus a perpendicular line will have a slope=-2/3.<BR>\n" );
document.write( "2=-2/3*-1+b<BR>\n" );
document.write( "2=2/3+b<BR>\n" );
document.write( "b=2-2/3<BR>\n" );
document.write( "b=(2*3-2)/3<BR>\n" );
document.write( "b=(6-2)/3<BR>\n" );
document.write( "b=4/3 is the Y intercept.<BR>\n" );
document.write( "Y=-2X/3+4/3. (green line)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+200%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+3x%2F2+-3+%2C+-2x%2F3+%2B4%2F3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+200%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+3x%2F2+-3+%2C+-2x%2F3+%2B4%2F3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 200x200 ixels, x from -5 to 5, y from -5 to 5, of TWO functions 3x/2 -3 and -2x/3 +4/3).  </SPAN>\n" );
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