document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332907>Question 332907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that 4 less than twice the second has the same value as three times the number that is one more than the third. \r<BR>\n" );
document.write( "\n" );
document.write( "Can someone please show me how to solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238537 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+2, x+4 be the 3 integers.<BR>\n" );
document.write( "2(x+2)-4=3(x+4+1)<BR>\n" );
document.write( "2x+4-4=3(x+5)<BR>\n" );
document.write( "2x=3x+15<BR>\n" );
document.write( "-x=15<BR>\n" );
document.write( "x=-15 ans for the smallest integer.<BR>\n" );
document.write( "-15+2=-13 for the second integer.<BR>\n" );
document.write( "-15+4=-11 for the third integer.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*-13-4=3(-11+1)<BR>\n" );
document.write( "-26-4=3*-10<BR>\n" );
document.write( "-26-4=-30<BR>\n" );
document.write( "-30=-30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );