document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38367>Question 38367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use this problem for #3 and 4. <BR>\n" );
document.write( "Lucy rides her bike 4 km/h faster than Kim. <BR>\n" );
document.write( "Lucy travels east for 2 hours. <BR>\n" );
document.write( "Kim travels west for 2 hours. <BR>\n" );
document.write( "They are then 80 km apart. <BR>\n" );
document.write( "How many km/h is Kim traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23853 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Remember D = RT, distance = rate*time.<BR>\n" );
document.write( "Let Kim's rate be r.<BR>\n" );
document.write( "Then Lucy's rate is r + 4.<BR>\n" );
document.write( "They both travel for 2 hours, so t = 2.<BR>\n" );
document.write( "Their total distance is 80 km, so we have<BR>\n" );
document.write( "2r + 2(r + 4) = 80<BR>\n" );
document.write( "2r + 2r + 8 = 80<BR>\n" );
document.write( "4r + 8 = 80<BR>\n" );
document.write( "4r = 72<BR>\n" );
document.write( "r = 18 km/h, Kim's rate. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );