document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332907>Question 332907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that 4 less than twice the second has the same value as three times the number that is one more than the third. \r<BR>\n" );
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document.write( "Can someone please show me how to solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238528 by </B><A HREF=/tutors/aboutme.mpl?userid=benazir.sj@gmail.com><B>benazir.sj@gmail.com(109)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=benazir.sj@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=benazir.sj@gmail.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "solution:<BR>\n" );
document.write( "Variables<BR>\n" );
document.write( "x = first consecutive odd integer<BR>\n" );
document.write( "x + 2 = second consecutive odd integer<BR>\n" );
document.write( "x + 4 = third consecutive odd integer\r<BR>\n" );
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document.write( "HINT: Break them up into smaller pieces if you're having trouble.\r<BR>\n" );
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document.write( "Given: 4 less <BR>\n" );
document.write( "Means: - 4\r<BR>\n" );
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document.write( "Given: than twice the second <BR>\n" );
document.write( "Means: 2 * (x + 2) = 2(x + 2)\r<BR>\n" );
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document.write( "Given: has the same value as <BR>\n" );
document.write( "Means: =\r<BR>\n" );
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document.write( "Given: three times<BR>\n" );
document.write( "Means: 3 *\r<BR>\n" );
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document.write( "Given: the number that is one more than third<BR>\n" );
document.write( "Means: 1 + x + 4 =\r<BR>\n" );
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document.write( "Put them all back together.\r<BR>\n" );
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document.write( "Given: 4 less than twice the second has the same value as three times the number that is one more than third. <BR>\n" );
document.write( "Means: 2(x + 2) - 4 = 3(1 + x + 4)\r<BR>\n" );
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document.write( "Simplify.<BR>\n" );
document.write( "2(x + 2) - 4 = 3(x + 5)\r<BR>\n" );
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document.write( "Distribute.<BR>\n" );
document.write( "2(x) + 2(2) - 4 = 3(x) + 3(5)<BR>\n" );
document.write( "2x + 4 - 4 = 3x + 15<BR>\n" );
document.write( "2x = 3x + 15\r<BR>\n" );
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document.write( "Subtract 3x from both sides.<BR>\n" );
document.write( "2x - 3x = 3x + 15 - 3x<BR>\n" );
document.write( "-x = 15\r<BR>\n" );
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document.write( "Divide both sides by -1.<BR>\n" );
document.write( "-x / -1 = 15 / -1<BR>\n" );
document.write( "x = -15\r<BR>\n" );
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document.write( "Plug this solved value into the variables.<BR>\n" );
document.write( "x = first consecutive odd integer = -15<BR>\n" );
document.write( "x + 2 = second consecutive odd integer = -15 + 2 = -13<BR>\n" );
document.write( "x + 4 = third consecutive odd integer = -15 + 4 = -11\r<BR>\n" );
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document.write( "ANSWER: The 3 numbers are -15, -13, and -11 </SPAN>\n" );
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