document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332896>Question 332896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertex of the parabola formed by the following quadratic function: y = -x2 + 10x - 1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238511 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "1. For ax^2 +bx+c parabola, the vertex (x,y) is such that x=-b/(2a) \r<BR>\n" );
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document.write( "for -x^2+10x-1,    x=-10/(-2*(-1)) =5,  y = -(5)^2+10*(5)-1=-25+50-1=24\r<BR>\n" );
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document.write( "vertex (5,24)\r<BR>\n" );
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document.write( "--<BR>\n" );
document.write( "there are many other ways to get the vertex<BR>\n" );
document.write( "* solve for the perfect square<BR>\n" );
document.write( "* Graph<BR>\n" );
document.write( "* take the derivative </SPAN>\n" );
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