document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38368>Question 38368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Franklin can ride his bike from his university to his home at 25 km/h. <BR>\n" );
document.write( "When he returns by car, he travels at 75 km/h. <BR>\n" );
document.write( "The bike trip is 2 hours longer than the car trip. <BR>\n" );
document.write( "How many kilometers is it from the university to Franklin's home? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23850 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Remember D = RT, distance = rate*time.<BR>\n" );
document.write( "Let us call his time for the first trip, t.  Thus the time on his return car trip is t - 2.  The distances are the same so we have<BR>\n" );
document.write( "25t = 75(t - 2)<BR>\n" );
document.write( "25t = 75t - 150<BR>\n" );
document.write( "-50t = -150<BR>\n" );
document.write( "t = 3<BR>\n" );
document.write( "So the distance is 25t or 75 miles. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );