document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38359>Question 38359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle has a perimeter of 3 meters. It's hypotonuse is 130 cm. What are the lengths of the other sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23846 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two legs be a and b.<BR>\n" );
document.write( "So we have a + b + 130 = 300 (300 cm is 3 m) and from the Pythagorean Theorem, we have<BR>\n" );
document.write( "a^2 + b^2 = 130^2<BR>\n" );
document.write( "Now solve the first equation for a and plug it in to the second equation, and solve using the factoring technique, so<BR>\n" );
document.write( "a + b = 170<BR>\n" );
document.write( "a = 170 - b<BR>\n" );
document.write( "(170 - b)^2 + b^2 = 16900<BR>\n" );
document.write( "28900 - 340b + b^2 + b^2 = 16900<BR>\n" );
document.write( "2b^2 - 340b + 12000 = 0<BR>\n" );
document.write( "b^2 - 170b + 6000 = 0<BR>\n" );
document.write( "(b - 120)(b - 50) = 0<BR>\n" );
document.write( "b = 120 or b = 50  thus<BR>\n" );
document.write( "a = 50 or a = 120 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );