document.write( "Question 332783: college algebra\r
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document.write( "use an equality and the five step process to solve the problem
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document.write( "dg's plumbing and heating charges $50 plus $65 per hour for emergency service. Bill remembers being billed just over $450 for an emergency call. how long to the nearest hour was the plumber at bill's house? \n" );
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Algebra.Com's Answer #238439 by mananth(16946)![]() ![]() You can put this solution on YOUR website! dg's plumbing and heating charges $50 plus $65 per hour \n" ); document.write( "billing $450 . \n" ); document.write( ".. \n" ); document.write( "let the number of hours worked be $x \n" ); document.write( "50+65x= 450 \n" ); document.write( "add -50 to both sides \n" ); document.write( "50-50+65x=450-50 \n" ); document.write( "65x=400 \n" ); document.write( "divide by 65 \n" ); document.write( "65x/65 = 400/65 \n" ); document.write( "x= 6.15 hours \n" ); document.write( "so plumber worked for about 6 hours \n" ); document.write( ".. \n" ); document.write( "CHECK \n" ); document.write( "50+6.15*65 = $449.75 \n" ); document.write( " |