document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332764>Question 332764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me with this and show me the steps.\r<BR>\n" );
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document.write( "-2x+4<22  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238434 by </B><A HREF=/tutors/aboutme.mpl?userid=barbiebig50><B>barbiebig50(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=barbiebig50><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2x +  4 < 22 The first step is to isolate the 2x. To do this the 4 needs to be eliminated and since it is added on the left we need to subtract it. It has to also be subtracted on the right. Next isolate the x by dividing by 2. remember you also have to divide by 2 on the right.\r<BR>\n" );
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document.write( "-2x + 4 -4 < 22 -4<BR>\n" );
document.write( "       2x < 18<BR>\n" );
document.write( "    2x/2 < 18/2<BR>\n" );
document.write( "       x < 9 is the solution<BR>\n" );
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