document.write( "Question 332713: two numbers differ by 12\r
\n" );
document.write( "\n" );
document.write( "a. if the smaller number is s, then the larger number is?
\n" );
document.write( "b. if the larger number is l, then the smaller number is? \n" );
document.write( "
Algebra.Com's Answer #238418 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let the numbers be x & y \n" ); document.write( "x-y=12 \n" ); document.write( "y=s \n" ); document.write( "x-s=12 \n" ); document.write( "add s to both sides \n" ); document.write( "x-s+s=12+s \n" ); document.write( "x=12+s the larger number \n" ); document.write( ".... \n" ); document.write( "... \n" ); document.write( "larger number is 1 \n" ); document.write( "x=1 \n" ); document.write( "1-y=12 \n" ); document.write( "add y to both sides \n" ); document.write( "1-y+y=12+y \n" ); document.write( "1=12+y \n" ); document.write( "add -12 to both sides \n" ); document.write( "1-12=12-12+y \n" ); document.write( "y=-11 the smaller number is -11 \n" ); document.write( " |