document.write( "Question 332713: two numbers differ by 12\r
\n" ); document.write( "\n" ); document.write( "a. if the smaller number is s, then the larger number is?
\n" ); document.write( "b. if the larger number is l, then the smaller number is?
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Algebra.Com's Answer #238418 by mananth(16946)\"\" \"About 
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\n" ); document.write( "let the numbers be x & y
\n" ); document.write( "x-y=12
\n" ); document.write( "y=s
\n" ); document.write( "x-s=12
\n" ); document.write( "add s to both sides
\n" ); document.write( "x-s+s=12+s
\n" ); document.write( "x=12+s the larger number
\n" ); document.write( "....
\n" ); document.write( "...
\n" ); document.write( "larger number is 1
\n" ); document.write( "x=1
\n" ); document.write( "1-y=12
\n" ); document.write( "add y to both sides
\n" ); document.write( "1-y+y=12+y
\n" ); document.write( "1=12+y
\n" ); document.write( "add -12 to both sides
\n" ); document.write( "1-12=12-12+y
\n" ); document.write( "y=-11 the smaller number is -11
\n" ); document.write( "
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