document.write( "Question 332699: A Triangle has sides that measures 12,9, and 15.
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document.write( "Find the area.
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document.write( "Find the perimeter \n" );
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Algebra.Com's Answer #238393 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter is the easy part, just add the measures of the three sides.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you divide each of the measures of the sides by 3, you notice that the three sides are in proportion \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In a right triangle, either of the legs can be considered the base of the triangle and the other leg is the height. The area of a triangle is the base times the height divided by 2. So just multiply 9 times 12 and divide by 2 to get the area.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |