document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332631>Question 332631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary if the sum of their measures is 180 degrees the measure of the first angle is 12 degrees less than two times the second angle<BR>\n" );
document.write( "what are the two angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238373 by </B><A HREF=/tutors/aboutme.mpl?userid=benazir.sj@gmail.com><B>benazir.sj@gmail.com(109)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=benazir.sj@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=benazir.sj@gmail.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the second angle  be x<BR>\n" );
document.write( "first angle is 12 degrees less than two times the second angle<BR>\n" );
document.write( "=2x-12<BR>\n" );
document.write( "given sum of there measures is 180<BR>\n" );
document.write( " x+2x-12 =180<BR>\n" );
document.write( "3x-12=180<BR>\n" );
document.write( "3x=180+12<BR>\n" );
document.write( "3x=192<BR>\n" );
document.write( "x =64<BR>\n" );
document.write( "second angle is 64<BR>\n" );
document.write( "first angle will be<BR>\n" );
document.write( "2x-12<BR>\n" );
document.write( "2*64-12<BR>\n" );
document.write( "128-12 =116<BR>\n" );
document.write( "116 and 64 are the measures of the two angles<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );