document.write( "Question 332481: the linear system has the solution (a,b,2)\r
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document.write( "2x-y-z=-3
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document.write( "x+2y-2z=-2
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document.write( "x+ky+z=5\r
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document.write( "determine the values of a,b and k \n" );
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Algebra.Com's Answer #238327 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the linear system has the solution (a,b,2) \n" ); document.write( "2x - y - z = -3 \n" ); document.write( " x +2y -2z =-2 \n" ); document.write( " x +ky + z = 5 \n" ); document.write( "determine the values of a,b and k \n" ); document.write( "rewrite each equation replacing z with 2, replace x & y with a and b \n" ); document.write( "2a - b - 2 = -3 \n" ); document.write( "2a - b = -3 + 2 \n" ); document.write( "2a - b = -1 \n" ); document.write( ": \n" ); document.write( "a + 2b - 2(2) = -2 \n" ); document.write( "a + 2b = -2 + 4 \n" ); document.write( "a + 2b = 2 \n" ); document.write( ": \n" ); document.write( "a + bk + 2 = 5 \n" ); document.write( "a + bk = 5 - 2 \n" ); document.write( "a + bk = 3 \n" ); document.write( ": \n" ); document.write( "Find b, multiply the 2nd equation by 2, subtract the 1st equation \n" ); document.write( "2a + 4b = 4 \n" ); document.write( "2a - b = -1 \n" ); document.write( "------------------eliminates a, find b \n" ); document.write( "5b = 5 \n" ); document.write( "b = 1 \n" ); document.write( ": \n" ); document.write( "Find a using, a + 2b = 2 \n" ); document.write( "a + 2(1) = 2 \n" ); document.write( "a = 2 - 2 \n" ); document.write( "a = 0 \n" ); document.write( ": \n" ); document.write( "Find k using the 3rd equation \n" ); document.write( "a + bk = 3 \n" ); document.write( "0 + 1k = 3 \n" ); document.write( "k = 3 \n" ); document.write( ": \n" ); document.write( "Summarize: a=0, b=1, k=3 \n" ); document.write( ": \n" ); document.write( "You can confirm these solutions in the original equations \n" ); document.write( " |