document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332525>Question 332525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of ABCD is 90 square inches. The length is ten times more then its width. What is the length? What is the width? What is the length of the diagonal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238316 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of ABCD is 90 square inches. The length is ten times more then its width. What is the length? What is the width? What is the length of the diagonal?<BR>\n" );
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document.write( "Area = L*W = 90<BR>\n" );
document.write( "L = 11W (10 times more = 11 times)<BR>\n" );
document.write( "Sub for L in the 1st eqn<BR>\n" );
document.write( "11W*W = 90<BR>\n" );
document.write( "W^2 = 90/11<BR>\n" );
document.write( "Width = sqrt(90/11) =~ 2.86 inches<BR>\n" );
document.write( "Length =~ 31.464 inches<BR>\n" );
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