document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332439>Question 332439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular aea is to enclosed by a fence then divided down the middle by another piece of fence then divided by another piece of fence .if 3600 metres of fence is available ,find the maximum area that can be enclosed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238311 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangular area is to enclosed by a fence then divided down the middle by <BR>\n" );
document.write( "another piece of fence then divided by another piece of fence .<BR>\n" );
document.write( "if 3600 metres of fence is available, find the maximum area that can be enclosed<BR>\n" );
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document.write( "From the description I see something like this<BR>\n" );
document.write( "______<BR>\n" );
document.write( "|_|_|_|; 3 enclosed areas<BR>\n" );
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document.write( "2L + 4W = 3600<BR>\n" );
document.write( "Simplify, divide by 2<BR>\n" );
document.write( "L + 2W = 1800<BR>\n" );
document.write( "L = (1800-2W)<BR>\n" );
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document.write( "A = L*W<BR>\n" );
document.write( "Replace L with (1800-2W)<BR>\n" );
document.write( "A = W(1800-2W)<BR>\n" );
document.write( "A quadratic equation<BR>\n" );
document.write( "A = -2W^2 + 1800W<BR>\n" );
document.write( "Max area occurs at axis of symmetry which is<BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1800%29%2F%282%2A-2%29 ALIGN=MIDDLE  ALT=\"%28-1800%29%2F%282%2A-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1800%29%2F%28-4%29 ALIGN=MIDDLE  ALT=\"%28-1800%29%2F%28-4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = 450 m, width for max area<BR>\n" );
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document.write( "Find L<BR>\n" );
document.write( "L = 1800-2(450)<BR>\n" );
document.write( "L = 900 m, length for max area<BR>\n" );
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document.write( "Find max area<BR>\n" );
document.write( "900 * 450 = 405,000 sq/m is max area<BR>\n" );
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