document.write( "Question 332495: The volume of rectangular solid with a square base is 216 cubic inches.What is
\n" ); document.write( "the least possible surface area for the solid?\r
\n" ); document.write( "\n" ); document.write( "(A) 24 in.2 (B) 72 in.2 (C) 216 in.2 (D) 252 in.2 (E) 492 in.2
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Algebra.Com's Answer #238282 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
This requires knowing the equation of the volume and surface area of rectangles\r
\n" ); document.write( "\n" ); document.write( "volume: (area of base)*height,
\n" ); document.write( "since base is a square and if its side is \"S\" then
\n" ); document.write( "\"volume+=+s%5E2%2AH\"\r
\n" ); document.write( "\n" ); document.write( "Surface area: 2* (area of the base) + (perimeter of the base) * height
\n" ); document.write( "\"Surface+Area+=2%2AS%5E2+%2B+4%2AS%2AH\"
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\n" ); document.write( "Solve the volume equation for H: \"H=Volume%2F%28S%5E2%29\"
\n" ); document.write( "substitute this into the surface area: \"2%2AS%5E2%2B4%2AS%2AH+=+2%2AS%5E2+%2B+4%2AS%28Volume%2F%28S%5E2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Surface area= \"SA=2%2AS%5E2+%2B+4%2Avolume%2FS+=+2%2AS%5E2+%2B+4%2A%28216%29%2FS+=+2%2AS%5E2%2B864%2FS\"
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\n" ); document.write( "Take the derivative of SA: (SA)' =\"+4%2AS+-864%2F%28S%5E2%29\"
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\n" ); document.write( "set this derivative =0 and solve for S
\n" ); document.write( "\"4S-864%2F%28S%5E2%29+=+0\"
\n" ); document.write( "\"4S=864%2F%28S%5E2%29\"
\n" ); document.write( "\"4S%5E3=864\"
\n" ); document.write( "\"S%5E3=216\"
\n" ); document.write( "S=6
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\n" ); document.write( "Check to see if this a minimum or maximum by taking the second derivative of SA
\n" ); document.write( "(SA)\" =\"+4-864%2A%28-2%29%2F%28S%5E3%29=4%2B3456%2F%28S%5E3%29\" evaluated at S=6
\n" ); document.write( "(SA)\"= \"4%2B3456%2F%286%5E3%29=20\", since its positive this means, the function curves upward, thus S=6 is a minimum
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\n" ); document.write( "Now substitute S=6 into the SA equation to find the lowest surface area
\n" ); document.write( "\"SA=+2%2AS%5E2%2B864%2FS+=+2%2A6%5E2%2B864%2F6=2%2A36%2B144=216\"\r
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