document.write( "Question 332461: I have asked this ? earlier with no response.
\n" );
document.write( "A ball is thrown from the top of a roof 320 feet above the ground. The formula h = –16t^2 + 32t + 320 describes the height of the ball above the ground, h, in feet, t seconds after the fall begins. Find the maximum height of the ball, as measured from the ground. Hint: The path of the ball is a parabola, so think about the vertex. \n" );
document.write( "
Algebra.Com's Answer #238281 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A ball is thrown from the top of a roof 320 feet above the ground. The formula h = –16t^2 + 32t + 320 describes the height of the ball above the ground, h, in feet, t seconds after the fall begins. Find the maximum height of the ball, as measured from the ground. Hint: The path of the ball is a parabola, so think about the vertex. \n" ); document.write( ". \n" ); document.write( "h = –16t^2 + 32t + 320 \n" ); document.write( "The vertex is a point (t,h) where the parabola is at its peak. \n" ); document.write( "\"axis of symmetry\" provides the \"t\" value of the vertex. \n" ); document.write( "The value is: \n" ); document.write( "t = -b/(2a) = -32/(2(-16)) \n" ); document.write( "t = -32/-32 \n" ); document.write( "t = 1 second \n" ); document.write( ". \n" ); document.write( "h value is found by plugging it back into the equation: \n" ); document.write( "h = –16t^2 + 32t + 320 \n" ); document.write( "h = –16(1)^2 + 32(1) + 320 \n" ); document.write( "h = –16 + 32 + 320 \n" ); document.write( "h = 16 + 320 \n" ); document.write( "h = 336 feet (this is your answer) \n" ); document.write( " |