document.write( "Question 332477: it took a patrol boat 5 hours to travel 80 km up a river against the current and 4 hours for the return trip with the current. find the speed of the boat in still water and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #238256 by mananth(16946)![]() ![]() You can put this solution on YOUR website! speed of boat = x kmph \n" ); document.write( "speed of current = y kmph \n" ); document.write( ".. \n" ); document.write( "speed upstream = x-y ;; Time =5 hours \n" ); document.write( "speed downstream = x+y;; Time= 4 hours \n" ); document.write( ".. \n" ); document.write( "distance = 80 km \n" ); document.write( ".. \n" ); document.write( "80/x-y = 5 \n" ); document.write( "80 =5x-5y \n" ); document.write( "16=x-y...............1 \n" ); document.write( ".. \n" ); document.write( "80/x+y=4 \n" ); document.write( "4x+4y=80 \n" ); document.write( "x+y=20...............2 \n" ); document.write( ".. \n" ); document.write( "add eq1 & 2 \n" ); document.write( "x+y+x-y=80+16 \n" ); document.write( "2x= 96 \n" ); document.write( "x= 96/2 \n" ); document.write( "x=48 km/h \n" ); document.write( ".. \n" ); document.write( "x-y=16 \n" ); document.write( "48-y=16 \n" ); document.write( "y=48-16 \n" ); document.write( "y=32 km/h \n" ); document.write( " |