document.write( "Question 332477: it took a patrol boat 5 hours to travel 80 km up a river against the current and 4 hours for the return trip with the current. find the speed of the boat in still water and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #238256 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
speed of boat = x kmph
\n" ); document.write( "speed of current = y kmph
\n" ); document.write( "..
\n" ); document.write( "speed upstream = x-y ;; Time =5 hours
\n" ); document.write( "speed downstream = x+y;; Time= 4 hours
\n" ); document.write( "..
\n" ); document.write( "distance = 80 km
\n" ); document.write( "..
\n" ); document.write( "80/x-y = 5
\n" ); document.write( "80 =5x-5y
\n" ); document.write( "16=x-y...............1
\n" ); document.write( "..
\n" ); document.write( "80/x+y=4
\n" ); document.write( "4x+4y=80
\n" ); document.write( "x+y=20...............2
\n" ); document.write( "..
\n" ); document.write( "add eq1 & 2
\n" ); document.write( "x+y+x-y=80+16
\n" ); document.write( "2x= 96
\n" ); document.write( "x= 96/2
\n" ); document.write( "x=48 km/h
\n" ); document.write( "..
\n" ); document.write( "x-y=16
\n" ); document.write( "48-y=16
\n" ); document.write( "y=48-16
\n" ); document.write( "y=32 km/h
\n" ); document.write( "
\n" );