document.write( "Question 332468: a student has money in 3 accounts that pay 5%, 7%, and 8% in annual interest. She has 3 times as much invested at 8% as she does at 5% If the total amount she has invested is $1600 and her interest for the year comes to $115, how much money does she have in each account? \n" ); document.write( "
Algebra.Com's Answer #238242 by mananth(16946)\"\" \"About 
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a student has money in 3 accounts that pay 5%, 7%, and 8% in annual interest. She has 3 times as much invested at 8% as she does at 5% If the total amount she has invested is $1600 and her interest for the year comes to $115, how much money does she have in each account?
\n" ); document.write( "..
\n" ); document.write( "5%-----------$x
\n" ); document.write( "8%-----------$3x
\n" ); document.write( "7%-----------$(1600-4x)
\n" ); document.write( "..
\n" ); document.write( "Interest = $115
\n" ); document.write( "..
\n" ); document.write( "sum of individual interests = 115
\n" ); document.write( "..
\n" ); document.write( "0.05x+0.08*3x+0.07*(1600-4x)=115
\n" ); document.write( "multiply by 100
\n" ); document.write( "5x+8*3x+7*(1600-4x)=11500
\n" ); document.write( "5x+24x+11200-28x=11500
\n" ); document.write( "x+11200=11500
\n" ); document.write( "x=11500-11200
\n" ); document.write( "x= 300 at 5%
\n" ); document.write( "300*3= 900 @8%
\n" ); document.write( "1600-1200=400 @7%
\n" ); document.write( "CHECK
\n" ); document.write( "0.05*300+0.08*900+0.07*400= 115
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