document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332464>Question 332464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the perimiter of the rectangle is 60 and the width is 12 what is the length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238240 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length be l<BR>\n" );
document.write( "width is 12<BR>\n" );
document.write( "perimeter = 2*(l+w)<BR>\n" );
document.write( "60=2*(l+12)<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "60/2 = 2*(l+12) / 2<BR>\n" );
document.write( "30=l+12<BR>\n" );
document.write( "add -12<BR>\n" );
document.write( "30-12=l+12-12<BR>\n" );
document.write( "18=l  the length.\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "18+18+12+12=60 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );