document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332460>Question 332460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle whose supplement measures 43 degrees more than twice its complement </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238235 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x deg<BR>\n" );
document.write( "supplement will be 180-x<BR>\n" );
document.write( "complement will be 90-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "supplement = 2(complement )+43\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "180-x=2(90-x)+43<BR>\n" );
document.write( "180-x=180-2x+43<BR>\n" );
document.write( "2x-x=43<BR>\n" );
document.write( "x=43 deg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );