document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4870>Question 4870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with solving the systems of equations by substitution and elimination.  Once I started working with solving this problem in the substituation method, I ran into fractions.  Is there a way to eliminate fractions early on?\r<BR>\n" );
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document.write( "4x + 7y =18<BR>\n" );
document.write( "5x - 3y = 2\r<BR>\n" );
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document.write( "I solved for x by getting x = -7y/4 + 18/4\r<BR>\n" );
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document.write( "Thanks!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2382 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you could make the first equation 20x+35y=90 and the second one 20x-12y=8, then find 20x= from the first and substitute that into the second. But you are doing more work here and defeating the object really of doing a substitution method: might as well just do the elimination method when both have 20x.\r<BR>\n" );
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document.write( "So, short answer is no - learn to work with fraction :-). Love fractions. Fractions are your friend lol\r<BR>\n" );
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document.write( "Enjoy.<BR>\n" );
document.write( "Jon. </SPAN>\n" );
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