document.write( "Question 332228: The braking distance (in feet) of a car going V mph is given by \"d%28v%29=v%5E2%2F20%2Bv\" v is greater or equal to 0.\r
\n" ); document.write( "\n" ); document.write( "how fast would the car have been traveling for a braking distance of 150feet? round to nearest mile per hour.
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Algebra.Com's Answer #238157 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
d(v)=v^2/20+v
\n" ); document.write( "(v^2/20)+v=150
\n" ); document.write( "v^2+20v=3000
\n" ); document.write( "v^2+20v-3000=0
\n" ); document.write( "v=46 mph Quadratic formula below
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B20x%2B-3000+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2820%29%5E2-4%2A1%2A-3000=12400\".
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\n" ); document.write( " Discriminant d=12400 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-20%2B-sqrt%28+12400+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2820%29%2Bsqrt%28+12400+%29%29%2F2%5C1+=+45.6776436283002\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2820%29-sqrt%28+12400+%29%29%2F2%5C1+=+-65.6776436283002\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B20x%2B-3000\" can be factored:
\n" ); document.write( " \"1x%5E2%2B20x%2B-3000+=+1%28x-45.6776436283002%29%2A%28x--65.6776436283002%29\"
\n" ); document.write( " Again, the answer is: 45.6776436283002, -65.6776436283002.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B20%2Ax%2B-3000+%29\"
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