document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332296>Question 332296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the complement of an angle to its supplement is 1 to 4.  Find the measure of the angle.  I know how to set up the problem x/180-x-60 = 1/4 which is x/120-x = 1/4 but I just don't know why they subtract the 60.  Please explain! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238146 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = given angle\r<BR>\n" );
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document.write( "So it's complement is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-x ALIGN=MIDDLE  ALT=\"90-x\"   DISABLED_style= \"max-width:90%; height:auto;\" > and it's supplement is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-x ALIGN=MIDDLE  ALT=\"180-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So if \"The ratio of the complement of an angle to its supplement is 1 to 4\", then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2890-x%29%2F%28180-x%29=1%2F4 ALIGN=MIDDLE  ALT=\"%2890-x%29%2F%28180-x%29=1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. I'll let you solve for x. </SPAN>\n" );
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