document.write( "Question 332263: solve: Log x + log(x-15) = 2 \n" ); document.write( "
Algebra.Com's Answer #238134 by edjones(8007)\"\" \"About 
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Log x + log(x-15) = 2
\n" ); document.write( "10^(log(x))*10^(log(x-15))=10^2
\n" ); document.write( "x(x-15)=100
\n" ); document.write( "x^2-15x-100=0
\n" ); document.write( "(x-20)(x+5)=0
\n" ); document.write( "x=20
\n" ); document.write( ".
\n" ); document.write( "Ed
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