document.write( "Question 332194: rendell father is 9times as old as he is.one year before he was 2years more that eleven times as old as rendell.find rendell present age. \n" ); document.write( "
Algebra.Com's Answer #238107 by mananth(16949)\"\" \"About 
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let rendell's age be x
\n" ); document.write( "father's age = 9x.
\n" ); document.write( "..
\n" ); document.write( "1 year ago their ages were
\n" ); document.write( "x-1
\n" ); document.write( "9x-1
\n" ); document.write( "..
\n" ); document.write( "9x-1=11(x-1)+2
\n" ); document.write( "9x-1=11x-11+2
\n" ); document.write( "9x-11x=-11+1+2
\n" ); document.write( "-2x=-8
\n" ); document.write( "x=4 Rendell's age now
\n" ); document.write( "father's age = 9*4=36 years\r
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