document.write( "Question 332215: 6 years ago, rosa was 4 times as old as her daughter. 10 years from now, she will be only twice as old. how old are they now? \n" ); document.write( "

Algebra.Com's Answer #238095 by mananth(16946) $\"\"$ $\"About$

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daughter age = x
\n" ); document.write( "6 years ago she was x-6
\n" ); document.write( "Rosa's age 6 years ago= 4(x-6)
\n" ); document.write( "..
\n" ); document.write( "10 years later daughter = x+10
\n" ); document.write( "Rosa will be 4*(x-6)+16
\n" ); document.write( "..
\n" ); document.write( "4*(x-6)+16=2*(x+10)
\n" ); document.write( "4x-24+16=2X+20
\n" ); document.write( "4x-2x=24-16+20
\n" ); document.write( "2x=28
\n" ); document.write( "divide by 2
\n" ); document.write( "2x/2 = 28/2
\n" ); document.write( "x= 14 daughter's age now.
\n" ); document.write( "10 years later Rosa's age = 4(x-6)+16
\n" ); document.write( "plug value of x
\n" ); document.write( "4(14-6)+16
\n" ); document.write( "=32+16
\n" ); document.write( "=48
\n" ); document.write( ".
\n" ); document.write( "Now Rosa's age will be 48-10
\n" ); document.write( "= 38. \n" ); document.write( "

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