document.write( "Question 332208: find the equation of the bisector of the acute angles and also the equation of the obtuse angles formed by the lines 7x-2y=4 and 3x+5y=15. \n" ); document.write( "

Algebra.Com's Answer #238094 by Alan3354(69443) $\"\"$ $\"About$

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find the equation of the bisector of the acute angles and also the equation of the obtuse angles formed by the lines 7x-2y=4 and 3x+5y=15.
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\n" ); document.write( "Find the slope of each line:
\n" ); document.write( "7x-2y = 4, m = 7/2
\n" ); document.write( "3x+5y =15, m = -3/5
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\n" ); document.write( "The slope is the tangent of the angle with the x-axis, so the arctan(m) is the angle.
\n" ); document.write( "Add the 2 angles, and divide by 2 --> the angle of the bisector.
\n" ); document.write( "Angle of bisector = (arctan(7/2) + arctan(-3/5))/2 = 21.5454 degs
\n" ); document.write( "The slope is the tangent, m = 0.3948
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\n" ); document.write( "Find the intersection of the lines 7x-2y=4 and 3x+5y=15.
\n" ); document.write( "It's (50/41,93/41) or (1.2195,2.2683)
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\n" ); document.write( "Use the point and y = mx+b to find b
\n" ); document.write( "2.2683 = 0.3948*1.2195 + b
\n" ); document.write( "b = 1.7868
\n" ); document.write( "Equation of the bisector: y = 0.3948x + 1.7868
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\n" ); document.write( "I don't what you mean by \"the equation of the obtuse angles\"
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