document.write( "Question 332138: Four numbers have a sum of 9900. The second exceeds the
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Algebra.Com's Answer #238063 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Four numbers have a sum of 9900. The second exceeds the\r\n" );
document.write( "first by one-seventh of the first. The third exceeds the sum\r\n" );
document.write( "of the first two by 300. The fourth exceeds the sum of the\r\n" );
document.write( "first three by 300. Find the four numbers.\r\n" );
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document.write( "Let a,b,c, and d respectively represent the first four numbers.\r\n" );
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\n" ); document.write( ">>...Four numbers have a sum of 9900...<<
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document.write( "That tells us that\r\n" );
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document.write( " a + b + c + d = 9900\r\n" );
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\n" ); document.write( ">>...The second exceeds the first by one-seventh of the first...<<
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document.write( "That tells us that\r\n" );
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document.write( "b = a + \"1%2F7\"a\r\n" );
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\n" ); document.write( ">>...The third exceeds the sum of the first two by 300...<<
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document.write( "That tells us that\r\n" );
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document.write( "c = (a + b) + 300\r\n" );
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\n" ); document.write( ">>...The fourth exceeds the sum of the first three by 300...<<
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document.write( "That tells us that\r\n" );
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document.write( "d = (a + b + c) + 300\r\n" );
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document.write( "So we have the system:\r\n" );
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document.write( "Simplify by removing parentheses and\r\n" );
document.write( "multiplying the second one through by 7\r\n" );
document.write( "to clear of fractions.\r\n" );
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document.write( "Simplify by combining terms in the 2nd one:\r\n" );
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document.write( "Simplify by rearranging terms:\r\n" );
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document.write( "Add the 1st and 4th equations term by term:\r\n" );
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document.write( "\"system%28%0D%0Aa+%2B+b+%2B+c+%2B+d+=+9900%2C%0D%0A-a+-+b+-+c+%2B+d=300%29\"\r\n" );
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document.write( "\"2d=10200\"\r\n" );
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document.write( "\"d=5100\"\r\n" );
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document.write( "So substitute that in the first three equations: \r\n" );
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document.write( "\"system%28%0D%0Aa+%2B+b+%2B+c+=+4800%2C%0D%0A-8a+%2B+7b+=+0%2C%0D%0A-a-b+%2Bc+=+300%29\"\r\n" );
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document.write( "Add the 1st and 3rd equation:\r\n" );
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document.write( "\"system%28%0D%0Aa+%2B+b+%2B+c+=+4800%2C%0D%0A-a-b+%2Bc+=+300%29\"\r\n" );
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document.write( "\"2c=5100\"\r\n" );
document.write( "\"c=2550\"\r\n" );
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document.write( "Substitute that in the first two\r\n" );
document.write( "equations:\r\n" );
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document.write( "\"system%28%0D%0Aa+%2B+b+%2B+c+=+4800%2C%0D%0A-8a+%2B+7b+=+0%29\"\r\n" );
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document.write( "\"system%28%0D%0Aa+%2B+b+%2B+2550+=+4800%2C%0D%0A-8a+%2B+7b+=+0%29\"\r\n" );
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document.write( "Rearrange:\r\n" );
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document.write( "\"system%28%0D%0Aa+%2B+b+=+2250%2C%0D%0A-8a+%2B+7b+=+0%29\"\r\n" );
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document.write( "To eliminate the a's multiply the first equation by 8\r\n" );
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document.write( "\"system%28%0D%0A8a+%2B+8b+=+18000%2C%0D%0A-8a+%2B+7b+=+0%29\"\r\n" );
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document.write( "Add term by term:\r\n" );
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document.write( "\"15b=18000\"\r\n" );
document.write( "\"b=1200\"\r\n" );
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document.write( "a = 1050, b = 1200, c = 2550, d = 5100 \r\n" );
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document.write( "Edwin
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