
\n" );
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document.write( "Since the leading term (tho one with the largest\r\n" );
document.write( "exponent is negative, we multiply every term by -1\r\n" );
document.write( "so the leading term will be positive. So we\r\n" );
document.write( "multiply through by -1. Thart changes all the signs:\r\n" );
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document.write( "
\r\n" );
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document.write( "Both the first term and the last term are perfect squares.\r\n" );
document.write( "The first term
is a perfect square, since it\r\n" );
document.write( "can be written as
. And the last term
can\r\n" );
document.write( "be written
.\r\n" );
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document.write( "So the whole trinomial is a candidate for being a perfect square.\r\n" );
document.write( "It may not be but we need to check to find out if it is actually\r\n" );
document.write( "a perfect square. Here is the test:\r\n" );
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document.write( "Multiply the square roots of the first and last terms on the left.\r\n" );
document.write( "Then double what you get. If you get the same thing as the middle \r\n" );
document.write( "term, or the middle term with the opposite sign, then it is a perfect\r\n" );
document.write( "square, and factors as \r\n" );
document.write( "\r\n" );
document.write( "(Square root of first term, sign of muddle term, Square root of last term)2\r\n" );
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document.write( "The square roots are 3x and 4. Multiply them. Get 12x.\r\n" );
document.write( "Then double that and get 24x. That is the same thing as the middle term \r\n" );
document.write( "-24x, with the opposite sign, so it is a perfect square, and factors as\r\n" );
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document.write( "
\r\n" );
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document.write( "So there is only one solution, found by setting\r\n" );
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document.write( "
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document.write( "
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document.write( "
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document.write( "Edwin
\r
\n" );
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