document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=332108>Question 332108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 104 miles per hour. Train A passes a station at 9:25 PM. If B passes the same station at 9:55 P.M at what time will train B catch up to A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238052 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=100T FOR TRAIN A.<BR>\n" );
document.write( "D=104(T-.5) FOR TRAIN B.<BR>\n" );
document.write( "THE DISTANCES ARE THE SAME SO SET THE 2 EQUATIONS EQUAL & SOLVE FOR T.<BR>\n" );
document.write( "100T=104(T-.5)<BR>\n" );
document.write( "100T=104T-52<BR>\n" );
document.write( "100T-104T=-52<BR>\n" );
document.write( "-4T=-52<BR>\n" );
document.write( "T=-52/-4<BR>\n" );
document.write( "T=13 HOURS AFTER TRAIN A LEAVES THE STATION TRAIN B WILL CATCH TRAIN A.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "100*13=104(13-.5)<BR>\n" );
document.write( "1,300=1,352-52<BR>\n" );
document.write( "1,300=1,300<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );