document.write( "Question 332078: Please help me factor the following completely:\r
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Algebra.Com's Answer #238010 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"6x%5E2-13x-5\", we can see that the first coefficient is \"6\", the second coefficient is \"-13\", and the last term is \"-5\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"6\" by the last term \"-5\" to get \"%286%29%28-5%29=-30\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-30\" (the previous product) and add to the second coefficient \"-13\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-30\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-30\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,5,6,10,15,30\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-30\".\r
\n" ); document.write( "\n" ); document.write( "1*(-30) = -30
\n" ); document.write( "2*(-15) = -30
\n" ); document.write( "3*(-10) = -30
\n" ); document.write( "5*(-6) = -30
\n" ); document.write( "(-1)*(30) = -30
\n" ); document.write( "(-2)*(15) = -30
\n" ); document.write( "(-3)*(10) = -30
\n" ); document.write( "(-5)*(6) = -30\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-13\":\r
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First NumberSecond NumberSum
1-301+(-30)=-29
2-152+(-15)=-13
3-103+(-10)=-7
5-65+(-6)=-1
-130-1+30=29
-215-2+15=13
-310-3+10=7
-56-5+6=1
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"2\" and \"-15\" add to \"-13\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"2\" and \"-15\" both multiply to \"-30\" and add to \"-13\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-13x\" with \"2x-15x\". Remember, \"2\" and \"-15\" add to \"-13\". So this shows us that \"2x-15x=-13x\".\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2Bhighlight%282x-15x%29-5\" Replace the second term \"-13x\" with \"2x-15x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%286x%5E2%2B2x%29%2B%28-15x-5%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%283x%2B1%29%2B%28-15x-5%29\" Factor out the GCF \"2x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%283x%2B1%29-5%283x%2B1%29\" Factor out \"5\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-5%29%283x%2B1%29\" Combine like terms. Or factor out the common term \"3x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"6x%5E2-13x-5\" factors to \"%282x-5%29%283x%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"6x%5E2-13x-5=%282x-5%29%283x%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%282x-5%29%283x%2B1%29\" to get \"6x%5E2-13x-5\" or by graphing the original expression and the answer (the two graphs should be identical).
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