document.write( "Question 332067: I need help. Find the equation of a line that is perpendicular to y=-x + 3 and passes through the point(-1, 2). \n" ); document.write( "
Algebra.Com's Answer #238005 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "We can see that the equation \"y=-x%2B3\" has a slope \"m=-1\" and a y-intercept \"b=3\".\r
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\n" ); document.write( "\n" ); document.write( "Now to find the slope of the perpendicular line, simply flip the slope \"m=-1\" to get \"m=-1%2F1\". Now change the sign to get \"m=1\". So the perpendicular slope is \"m=1\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope \"m=1\" and the coordinates of the given point .\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=1%28x--1%29\" Plug in \"m=1\", \"x%5B1%5D=-1\", and \"y%5B1%5D=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=1%28x%2B1%29\" Rewrite \"x--1\" as \"x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=1x%2B1%281%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=1x%2B1\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=1x%2B1%2B2\" Add 2 to both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"y=1x%2B3\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"y=x%2B3\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line perpendicular to \"y=-x%2B3\" that goes through the point is \"y=x%2B3\".\r
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\n" ); document.write( "\n" ); document.write( "Here's a graph to visually verify our answer:\r
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\n" ); document.write( "\n" ); document.write( "Graph of the original equation \"y=-x%2B3\" (red) and the perpendicular line \"y=x%2B3\" (green) through the point .
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