document.write( "Question 4873: I am completely stuck on this problem. Help!\r
\n" ); document.write( "\n" ); document.write( "Graph the fuction:
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\n" ); document.write( "\"f+%28x%29=+2%5E4x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"g+%28x%29=+3+%2Alog%282%2C%28x-7%29%29\"\r
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Algebra.Com's Answer #2380 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
graphing....learn the basic shapes first then apply that knowledge to more complicated ones. So \"y=2%5Ex\" (or any exponential function) looks like:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28200%2C200%2C-4%2C5%2C-6%2C40%2C+2%5Ex%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note 2 things:\r
\n" ); document.write( "\n" ); document.write( "1. it does not go below the x-axis, since there is no value of x that can make y negative. In fact as x becomes more negative, the curve approaches the x-axis, ie approaches y=0. This \"approaching, but never quite reaching\" characteristic is called the asymptote.\r
\n" ); document.write( "\n" ); document.write( "2. the curve rises rapidly to infinity as x increases.\r
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\n" ); document.write( "\n" ); document.write( "So, what about \"f%28x%29+=+2%5E4x%2B4\"? First thing is USE BRACKETS!!!! because i do not know if you mean \"f%28x%29+=+2%5E%284x%2B4%29\" or \"f%28x%29+=+2%5E%284x%29%2B4\". So i shall do both!\r
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\n" ); document.write( "\n" ); document.write( "1. \"f%28x%29+=+2%5E%284x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "we know the rough shape. Just need to know the asymptote and any values where the curve crosses the axes.\r
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\n" ); document.write( "\n" ); document.write( "Any value of x gives a whole range of possible values of 4x+4. All of these, as powers of 2 will never give a negative answer for y. So the curve, again, does not go below the x-axis...ie the asymptote is y=0.\r
\n" ); document.write( "\n" ); document.write( "Voila, all we need now is find where the curve crosses the y=axis (ie where x=0)... \"y+=+2%5E%284x%2B4%29\" --> \"y+=+2%5E%284%280%29%2B4%29\" --> \"y+=+2%5E4\" --> y=16.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28200%2C200%2C-2%2C1%2C-3%2C300%2C+2%5E%284x%2B4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "see how this is exactly the same type of curve but the axes scales are hugely different.\r
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\n" ); document.write( "\n" ); document.write( "2. \"f%28x%29+=+2%5E%284x%29%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Again, we know the rough shape..any value of x will never give a negative answer, so never below y=0. However, we then add 4 to all answers, so our asymptote is now no longer y=0, but y=4.\r
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\n" ); document.write( "\n" ); document.write( "Find where the curve crosses the y-axis (where x=0)...\"f%28x%29+=+2%5E%284x%29%2B4\" --> \"f%280%29+=+y+=+2%5E%280%29%2B4\" --> \"y+=+1%2B4\" --> y=5\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28200%2C200%2C-2%2C1%2C-3%2C30%2C+2%5E%284x%29%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Hope this all helps. Learn the following basic shapes:\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+x%5E2\"
\n" ); document.write( "\"f%28x%29+=+x%5E3\"
\n" ); document.write( "\"f%28x%29+=+x%5E3+%2B+other+terms\"
\n" ); document.write( "\"f%28x%29+=+1%2Fx\"
\n" ); document.write( "\"f%28x%29+=+2%5Ex\"
\n" ); document.write( "\"f%28x%29+=+log%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "More complex versions of each type have their own characters but at least it is a start :-)\r
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\n" ); document.write( "\n" ); document.write( "jon
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