document.write( "Question 332015: Solve: 2 * Log base 4(x) + 3 * log base 8(x) = 10 \n" ); document.write( "
Algebra.Com's Answer #237997 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
\"2+%2A+log%284%2Cx%29+%2B+3+%2A+log%288%2Cx%29+=+10\"
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\n" ); document.write( "\n" ); document.write( "need to put both logs in same base, choose one base does not matter\r
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\n" ); document.write( "\"log%288%2Cx%29=log%284%2Cx%29%2Flog%284%2C8%29\"
\n" ); document.write( "also \"log%284%2C8%29=log%282%2C8%29%2Flog%282%2C4%29=log%282%2C2%29%5E3%2Flog%282%2C2%29%5E2=3%2F2\"\r
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\n" ); document.write( "so...
\n" ); document.write( "\"log%288%2Cx%29=log%284%2Cx%29%2F%283%2F2%29=2%2F3%2Alog%284%2Cx%29\"
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\n" ); document.write( "\"log%284%2Cx%29=10%2F4=5%2F2\"
\n" ); document.write( "--\r
\n" ); document.write( "\n" ); document.write( "\"4%5E%28log%284%2Cx%29%29=4%5E%285%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "remember that \"a%5E%28log%28a%2Cx%29%29=x\"\r
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\n" ); document.write( "x=\"4%5E%285%2F2%29=+%282%5E%282%29%29%5E%285%2F2%29=2%5E5+=32\"\r
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