document.write( "Question 38302: Divide\r
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document.write( "A. Use long division to divide x³+6x²-x-30 by x²+8x+15\r
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document.write( "B. Use synthetic division to divide (x³+5x²-18)/(x+3) \n" );
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Algebra.Com's Answer #23795 by junior403(76)![]() ![]() ![]() You can put this solution on YOUR website! A. Use long division to divide x³+6x²-x-30 by x²+8x+15 \n" ); document.write( "We set up a long division problem like this... \n" ); document.write( " _______________ \n" ); document.write( "x^2+8x+15)X^3+6x^2-x-30 \n" ); document.write( "We can now start with the first variable (X^2)and find the value that will make the divisor (x^3) true. (x^2 * x = x^3) \n" ); document.write( "Then multiply that answer by the remaining variables. (x * 8x = 8x^2) and (x * 15 = 15x) Then we distribute a negative to subtract that line from the top line to get a new set of numbers...and repeat. \n" ); document.write( "x^2 multiplied by what makes -2x^2, and so on just like long division w/real numbers... \n" ); document.write( "So... \n" ); document.write( "_______________x_-_2_______ \n" ); document.write( "x^2+8x+15)x^3+6x^2 - x -30 \n" ); document.write( "________-(x^3+8x^2+15x) \n" ); document.write( "_____________-2x^2-16x -30 \n" ); document.write( "____________+2X^2+16X +30 \n" ); document.write( "_______________________0\r \n" ); document.write( "\n" ); document.write( "The answer is x-2. \n" ); document.write( "To check, simply multiply x^2+8x+15(x-2) = x^3+6x^2-x-30 \n" ); document.write( "Its kind of hard to show all the work here, but I hope you get the idea. \n" ); document.write( "B. Use synthetic division to divide (x³+5x²-18)/(x+3) \n" ); document.write( "This process can be a little tricky. \n" ); document.write( "First we change the x+3 into x-(-3) \n" ); document.write( "Now just write the coefficients of x^3 5x^2 18 with -3 on the left \n" ); document.write( "-3)1 5 18 (set up like long division) \n" ); document.write( "First carry down the 1 by itself. \n" ); document.write( "-3)1 5 18 \n" ); document.write( "____________ \n" ); document.write( "__1 \n" ); document.write( "Then multiply -3(1) and place the answer under the second column. \n" ); document.write( "-3)1 5 18 \n" ); document.write( "___-3____ \n" ); document.write( "__1 \n" ); document.write( "Then subtract... \n" ); document.write( "-3)1 5 18 \n" ); document.write( "___-3____ \n" ); document.write( "__1_2 \n" ); document.write( "then multiply the -3 by that result... \n" ); document.write( "-3)1 5 18 \n" ); document.write( "___-3-6 \n" ); document.write( "__1_2 \n" ); document.write( "And subtract... \n" ); document.write( "-3)1 5 18 \n" ); document.write( "___-3-6 \n" ); document.write( "__1_2_12 (12 is the remainder, so it is written over the divisor x+3) \n" ); document.write( "Now the result 1 2 12 can take the original signs... \n" ); document.write( "1x + 2 -12/x+3 \n" ); document.write( "And this is the final answer... \n" ); document.write( "I hope this helps. \n" ); document.write( "Let me know if you have any further questions about this. \n" ); document.write( "Thanks. \n" ); document.write( "Good Luck!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good Luck! \n" ); document.write( " |