document.write( "Question 330282: The width of a rectangle is 4ft less than the length. The area is 12ft^2. Find the length and the width. \n" ); document.write( "

Algebra.Com's Answer #237915 by privani(34) $\"\"$ $\"About$

You can put this solution on YOUR website!
Assuming length = a, and width = b = a-4.
\n" ); document.write( "Area = a*b = 12
\n" ); document.write( " $\"a%2A%28a-4%29+=+12\"$
\n" ); document.write( " $\"a%5E2+-+4a+=+12\"$
\n" ); document.write( " $\"a%5E2+-+4a+-+12+=+0\"$
\n" ); document.write( " $\"%28a%2B2%29%28a-6%29+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "a + 2 = 0
\n" ); document.write( "a = -2; not impossible.\r
\n" ); document.write( "\n" ); document.write( "a - 6 = 0
\n" ); document.write( "a = 6\r
\n" ); document.write( "\n" ); document.write( "If a = 6, then
\n" ); document.write( "a*b = 12
\n" ); document.write( "6b = 12
\n" ); document.write( "b = 12/6 = 2\r
\n" ); document.write( "\n" ); document.write( "Hence, length = 6 feet and width = 2 feet. \n" ); document.write( "

\n" );