document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331918>Question 331918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a two digit number is three times the sum of each digit. If 45 is addad to the number, the digit reverses. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237909 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be xy.\r<BR>\n" );
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document.write( "10x+y= 3(x+y)<BR>\n" );
document.write( "10x+y=3x+3y<BR>\n" );
document.write( "7x-2y=0...................1<BR>\n" );
document.write( "..<BR>\n" );
document.write( "10x+y+45 = 10y+x<BR>\n" );
document.write( "9x-9y=-45<BR>\n" );
document.write( "x-y=-5....................2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "multiply equation 2 by -2 and add to equation 1<BR>\n" );
document.write( "-2(x-y)+7x-2y=10+0<BR>\n" );
document.write( "-2x+2y+7x-2y=10<BR>\n" );
document.write( "5x=10<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x-y=-5<BR>\n" );
document.write( "2-y=-5<BR>\n" );
document.write( "y=7<BR>\n" );
document.write( "the number is 27<BR>\n" );
document.write( " </SPAN>\n" );
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