document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331861>Question 331861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> While moving with the current of the water, Sally can kayak across 4 miles of a lake in the same amount of time it takes her to travel 3 miles against the current. If the current is found to be .5 mph, find Sally's rate in still water.\r<BR>\n" );
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document.write( "I know the formula D=RT but I am stumped!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237907 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how about D/R=T ___ the times are the same\r<BR>\n" );
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document.write( "4/(s + c) = 3/(s - c) ___ c = .5\r<BR>\n" );
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document.write( "\"cross\" multiplying ___ 4s - 2 = 3s + 1.5\r<BR>\n" );
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document.write( "s = 3.5 </SPAN>\n" );
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